Can anyone explain how to do a multi-step algerbra expression without negative numbers?

Please answer as soon as possible! I really dont understand so please explain!Can anyone explain how to do a multi-step algerbra expression without negative numbers?
I'm going to have to guess what you mean.


Example: x^-2y^5 / x^-4y-2


One of the Laws of Exponents is that a^-n=1/a^n


This law comes about as follows:


x^5/x^3= xxxxx/xxx, or x^2


LAW: when dividing exponential terms whose bases


are identical, just subtract the exponents. Thus,


x^5/x^3=x^(5-3), or x^2


Well, what happens if the problem is x^3/x^5?


That's xxx/xxxxx, or 1/x^2. Yet by the LAW for


Division just defined earlier, x^3/x^5=x^(3-5), =x^-2!


Well , x^3/x^5=1/x^2 and x^3/x^5=x^-2


Therefore 1/x^2=x^-2


And therein lies the secret to getting rid of negative


exponents.


For our invented problem x^-2y^5 / x^-4y^-2, we


proceed as follows:


x^-2 is 1/x^2. y^5 stays the same. x^-4 is 1/x^4, and y^-2 is 1/y^2.


We get (1/x^2)(y^5) / (1/x^4)(1/y^2)


=y^5/x^2 / 1/x^4y^2


=y^5 / x^2 X x^4y^2


x^4y^7/x^2


=x^2y^7





There is a short-cut.


x^-2y^5 / x^-4y^-2


Move negative exponential terms to the denominator


or numerator and change the sign of the exponent.


x^-2y^5 / x-4y^-2 becomes y^5x^4y^2/x^2


=x^4y^7/x^2


=x^2y^7





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